USM STAN 2013

Tukang Tanya
· 6 bulan yang lalu

$open parentheses square root of 196 minus 9 close parentheses plus fraction numerator 3 square root of 36 cross times begin display style fraction numerator 1 over denominator square root of 9 end fraction end style over denominator 0 comma 2500 end fraction minus open parentheses 2 cubed minus fraction numerator square root of 8 over denominator square root of 2 end fraction close parentheses equals...$
A. 20 D. 23
B. 21 E. 24
C. 2
Fahrizal
· 6 bulan yang lalu

$open parentheses square root of 196 minus 9 close parentheses plus fraction numerator 3 square root of 36 cross times begin display style fraction numerator 1 over denominator square root of 9 end fraction end style over denominator 0 comma 2500 end fraction minus open parentheses 2 cubed minus fraction numerator square root of 8 over denominator square root of 2 end fraction close parentheses equals space open parentheses 14 minus 9 close parentheses space plus space fraction numerator 18 divided by 3 over denominator 1 divided by 4 end fraction minus open parentheses 8 minus square root of 4 close parentheses equals space 5 plus 24 minus 6 equals 23 K u n c i space D$

Pengguna Teratas

Tukang Tanya 3234

106 · 2

Teski

40 · 50

Fahrizal

2 · 46

Dian Septiana

19 · 26

fahrizal rambe

5 · 4

Terbaru